Base | Representation |
---|---|
bin | 1110001010011100010100… |
… | …01001001011011010100111 |
3 | 11002021110000100101201102111 |
4 | 13011032022021023122213 |
5 | 13040240204113301114 |
6 | 150123512333221451 |
7 | 6363106146634462 |
oct | 705161211133247 |
9 | 132243010351374 |
10 | 31145125525159 |
11 | 9a18634452a98 |
12 | 35b0173631887 |
13 | 144bc851383a9 |
14 | 799609a3a2d9 |
15 | 390252210bc4 |
hex | 1c538a24b6a7 |
31145125525159 has 2 divisors, whose sum is σ = 31145125525160. Its totient is φ = 31145125525158.
The previous prime is 31145125525079. The next prime is 31145125525231. The reversal of 31145125525159 is 95152552154113.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 31145125525159 - 217 = 31145125394087 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (31145125529159) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15572562762579 + 15572562762580.
It is an arithmetic number, because the mean of its divisors is an integer number (15572562762580).
Almost surely, 231145125525159 is an apocalyptic number.
31145125525159 is a deficient number, since it is larger than the sum of its proper divisors (1).
31145125525159 is an equidigital number, since it uses as much as digits as its factorization.
31145125525159 is an evil number, because the sum of its binary digits is even.
The product of its digits is 1350000, while the sum is 49.
The spelling of 31145125525159 in words is "thirty-one trillion, one hundred forty-five billion, one hundred twenty-five million, five hundred twenty-five thousand, one hundred fifty-nine".
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