Base | Representation |
---|---|
bin | 1001000100001001011… |
… | …01010000000111110101 |
3 | 1002202221110122122222001 |
4 | 10202010231100013311 |
5 | 20100334302202331 |
6 | 355030140335301 |
7 | 31334241112402 |
oct | 4420455200765 |
9 | 1082843578861 |
10 | 311464100341 |
11 | 110100401599 |
12 | 50444844531 |
13 | 234a8c4bc34 |
14 | 111099012a9 |
15 | 817dd74561 |
hex | 4884b501f5 |
311464100341 has 2 divisors, whose sum is σ = 311464100342. Its totient is φ = 311464100340.
The previous prime is 311464100323. The next prime is 311464100351. The reversal of 311464100341 is 143001464113.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 246160853316 + 65303247025 = 496146^2 + 255545^2 .
It is an emirp because it is prime and its reverse (143001464113) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-311464100341 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (311464100351) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 155732050170 + 155732050171.
It is an arithmetic number, because the mean of its divisors is an integer number (155732050171).
Almost surely, 2311464100341 is an apocalyptic number.
It is an amenable number.
311464100341 is a deficient number, since it is larger than the sum of its proper divisors (1).
311464100341 is an equidigital number, since it uses as much as digits as its factorization.
311464100341 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3456, while the sum is 28.
Adding to 311464100341 its reverse (143001464113), we get a palindrome (454465564454).
The spelling of 311464100341 in words is "three hundred eleven billion, four hundred sixty-four million, one hundred thousand, three hundred forty-one".
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