Base | Representation |
---|---|
bin | 1110001010100110001011… |
… | …11010010100101101101110 |
3 | 11002021221200112222002002121 |
4 | 13011103011322110231232 |
5 | 13040332031321400332 |
6 | 150130150141343154 |
7 | 6363354345456142 |
oct | 705230572245556 |
9 | 132257615862077 |
10 | 31150423231342 |
11 | 9a1a902908068 |
12 | 35b11b1867aba |
13 | 144c61a87098c |
14 | 79998d475222 |
15 | 390462371797 |
hex | 1c54c5e94b6e |
31150423231342 has 8 divisors (see below), whose sum is σ = 46726514183736. Its totient is φ = 15574918503432.
The previous prime is 31150423231339. The next prime is 31150423231379. The reversal of 31150423231342 is 24313232405113.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a super-3 number, since 3×311504232313423 (a number of 41 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a junction number, because it is equal to n+sod(n) for n = 31150423231298 and 31150423231307.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 146423253 + ... + 146635840.
It is an arithmetic number, because the mean of its divisors is an integer number (5840814272967).
Almost surely, 231150423231342 is an apocalyptic number.
31150423231342 is a deficient number, since it is larger than the sum of its proper divisors (15576090952394).
31150423231342 is a wasteful number, since it uses less digits than its factorization.
31150423231342 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 293112242.
The product of its (nonzero) digits is 51840, while the sum is 34.
Adding to 31150423231342 its reverse (24313232405113), we get a palindrome (55463655636455).
The spelling of 31150423231342 in words is "thirty-one trillion, one hundred fifty billion, four hundred twenty-three million, two hundred thirty-one thousand, three hundred forty-two".
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