Base | Representation |
---|---|
bin | 101101010101001100010… |
… | …111001000011110000111 |
3 | 102000210200221020022020202 |
4 | 231111030113020132013 |
5 | 402014242400001043 |
6 | 10343023322521115 |
7 | 441026612461046 |
oct | 55251427103607 |
9 | 12023627208222 |
10 | 3115132422023 |
11 | aa113604a486 |
12 | 42389766619b |
13 | 1979a94416cb |
14 | aaab79ac55d |
15 | 560721ee1b8 |
hex | 2d54c5c8787 |
3115132422023 has 2 divisors, whose sum is σ = 3115132422024. Its totient is φ = 3115132422022.
The previous prime is 3115132421983. The next prime is 3115132422113. The reversal of 3115132422023 is 3202242315113.
3115132422023 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 3115132422023 - 216 = 3115132356487 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (3115132452023) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1557566211011 + 1557566211012.
It is an arithmetic number, because the mean of its divisors is an integer number (1557566211012).
Almost surely, 23115132422023 is an apocalyptic number.
3115132422023 is a deficient number, since it is larger than the sum of its proper divisors (1).
3115132422023 is an equidigital number, since it uses as much as digits as its factorization.
3115132422023 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 8640, while the sum is 29.
Adding to 3115132422023 its reverse (3202242315113), we get a palindrome (6317374737136).
The spelling of 3115132422023 in words is "three trillion, one hundred fifteen billion, one hundred thirty-two million, four hundred twenty-two thousand, twenty-three".
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