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3115132422023 is a prime number
BaseRepresentation
bin101101010101001100010…
…111001000011110000111
3102000210200221020022020202
4231111030113020132013
5402014242400001043
610343023322521115
7441026612461046
oct55251427103607
912023627208222
103115132422023
11aa113604a486
1242389766619b
131979a94416cb
14aaab79ac55d
15560721ee1b8
hex2d54c5c8787

3115132422023 has 2 divisors, whose sum is σ = 3115132422024. Its totient is φ = 3115132422022.

The previous prime is 3115132421983. The next prime is 3115132422113. The reversal of 3115132422023 is 3202242315113.

3115132422023 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 3115132422023 - 216 = 3115132356487 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (3115132452023) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1557566211011 + 1557566211012.

It is an arithmetic number, because the mean of its divisors is an integer number (1557566211012).

Almost surely, 23115132422023 is an apocalyptic number.

3115132422023 is a deficient number, since it is larger than the sum of its proper divisors (1).

3115132422023 is an equidigital number, since it uses as much as digits as its factorization.

3115132422023 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 8640, while the sum is 29.

Adding to 3115132422023 its reverse (3202242315113), we get a palindrome (6317374737136).

The spelling of 3115132422023 in words is "three trillion, one hundred fifteen billion, one hundred thirty-two million, four hundred twenty-two thousand, twenty-three".