3116113255133 has 2 divisors, whose sum is σ = 3116113255134. Its totient is φ = 3116113255132.

The previous prime is 3116113255127. The next prime is 3116113255163. The reversal of 3116113255133 is 3315523116113.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 3115500346084 + 612909049 = 1765078^2 + 24757^2 .

It is a cyclic number.

It is not a de Polignac number, because 3116113255133 - 2⁴⁰ = 2016601627357 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 3116113255093 and 3116113255102.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (3116113255163) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1558056627566 + 1558056627567.

It is an arithmetic number, because the mean of its divisors is an integer number (1558056627567).

Almost surely, 2^{3116113255133} is an apocalyptic number.

It is an amenable number.

3116113255133 is a deficient number, since it is larger than the sum of its proper divisors (1).

3116113255133 is an equidigital number, since it uses as much as digits as its factorization.

3116113255133 is an evil number, because the sum of its binary digits is even.

The product of its digits is 24300, while the sum is 35.

The spelling of 3116113255133 in words is "three trillion, one hundred sixteen billion, one hundred thirteen million, two hundred fifty-five thousand, one hundred thirty-three".