Base | Representation |
---|---|
bin | 101101010110001110100… |
… | …111101101000101010111 |
3 | 102000220120101222111101011 |
4 | 231112032213231011113 |
5 | 402024031440000201 |
6 | 10343325513113051 |
7 | 441066301325404 |
oct | 55261647550527 |
9 | 12026511874334 |
10 | 3116244062551 |
11 | aa1656595464 |
12 | 423b479b8787 |
13 | 197b25839879 |
14 | aab8149b2ab |
15 | 560d9ad4151 |
hex | 2d58e9ed157 |
3116244062551 has 2 divisors, whose sum is σ = 3116244062552. Its totient is φ = 3116244062550.
The previous prime is 3116244062531. The next prime is 3116244062563. The reversal of 3116244062551 is 1552604426113.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 3116244062551 - 237 = 2978805109079 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (3116244062531) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1558122031275 + 1558122031276.
It is an arithmetic number, because the mean of its divisors is an integer number (1558122031276).
Almost surely, 23116244062551 is an apocalyptic number.
3116244062551 is a deficient number, since it is larger than the sum of its proper divisors (1).
3116244062551 is an equidigital number, since it uses as much as digits as its factorization.
3116244062551 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 172800, while the sum is 40.
Adding to 3116244062551 its reverse (1552604426113), we get a palindrome (4668848488664).
The spelling of 3116244062551 in words is "three trillion, one hundred sixteen billion, two hundred forty-four million, sixty-two thousand, five hundred fifty-one".
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