Base | Representation |
---|---|
bin | 111011011100… |
… | …0011001110001 |
3 | 2011122021222212 |
4 | 1312320121301 |
5 | 30434222032 |
6 | 3031541505 |
7 | 525614123 |
oct | 166703161 |
9 | 64567885 |
10 | 31164017 |
11 | 16655a95 |
12 | a52a895 |
13 | 65c1a61 |
14 | 41d3213 |
15 | 2b08bb2 |
hex | 1db8671 |
31164017 has 2 divisors, whose sum is σ = 31164018. Its totient is φ = 31164016.
The previous prime is 31163969. The next prime is 31164019. The reversal of 31164017 is 71046113.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 28344976 + 2819041 = 5324^2 + 1679^2 .
It is an emirp because it is prime and its reverse (71046113) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 31164017 - 218 = 30901873 is a prime.
Together with 31164019, it forms a pair of twin primes.
It is a Chen prime.
It is a junction number, because it is equal to n+sod(n) for n = 31163983 and 31164001.
It is not a weakly prime, because it can be changed into another prime (31164019) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15582008 + 15582009.
It is an arithmetic number, because the mean of its divisors is an integer number (15582009).
Almost surely, 231164017 is an apocalyptic number.
It is an amenable number.
31164017 is a deficient number, since it is larger than the sum of its proper divisors (1).
31164017 is an equidigital number, since it uses as much as digits as its factorization.
31164017 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 504, while the sum is 23.
The square root of 31164017 is about 5582.4740930881. The cubic root of 31164017 is about 314.6911123390.
The spelling of 31164017 in words is "thirty-one million, one hundred sixty-four thousand, seventeen".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.074 sec. • engine limits •