Base | Representation |
---|---|
bin | 101101011000011101110… |
… | …110110011100010000101 |
3 | 102001010202212211122110222 |
4 | 231120131312303202011 |
5 | 402043442133204023 |
6 | 10344404155554125 |
7 | 441212661334244 |
oct | 55303566634205 |
9 | 12033685748428 |
10 | 3118647163013 |
11 | aa267a0253a8 |
12 | 4244b875b945 |
13 | 19811966c7c5 |
14 | aad2c6c695b |
15 | 561caa6dcc8 |
hex | 2d61ddb3885 |
3118647163013 has 2 divisors, whose sum is σ = 3118647163014. Its totient is φ = 3118647163012.
The previous prime is 3118647163007. The next prime is 3118647163043. The reversal of 3118647163013 is 3103617468113.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 3084319225729 + 34327937284 = 1756223^2 + 185278^2 .
It is a cyclic number.
It is not a de Polignac number, because 3118647163013 - 236 = 3049927686277 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (3118647163043) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1559323581506 + 1559323581507.
It is an arithmetic number, because the mean of its divisors is an integer number (1559323581507).
Almost surely, 23118647163013 is an apocalyptic number.
It is an amenable number.
3118647163013 is a deficient number, since it is larger than the sum of its proper divisors (1).
3118647163013 is an equidigital number, since it uses as much as digits as its factorization.
3118647163013 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 217728, while the sum is 44.
The spelling of 3118647163013 in words is "three trillion, one hundred eighteen billion, six hundred forty-seven million, one hundred sixty-three thousand, thirteen".
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