Base | Representation |
---|---|
bin | 1001000101000001111… |
… | …01111011100101111011 |
3 | 1002211011111211012002121 |
4 | 10202200331323211323 |
5 | 20102322142002442 |
6 | 355145154542111 |
7 | 31352056150426 |
oct | 4424075734573 |
9 | 1084144735077 |
10 | 311938234747 |
11 | 110324001807 |
12 | 50557597937 |
13 | 23553248b39 |
14 | 111528829bd |
15 | 81aa7cd967 |
hex | 48a0f7b97b |
311938234747 has 2 divisors, whose sum is σ = 311938234748. Its totient is φ = 311938234746.
The previous prime is 311938234723. The next prime is 311938234799. The reversal of 311938234747 is 747432839113.
It is an a-pointer prime, because the next prime (311938234799) can be obtained adding 311938234747 to its sum of digits (52).
It is a weak prime.
It is an emirp because it is prime and its reverse (747432839113) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 311938234747 - 231 = 309790751099 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 311938234694 and 311938234703.
It is not a weakly prime, because it can be changed into another prime (311938231747) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 155969117373 + 155969117374.
It is an arithmetic number, because the mean of its divisors is an integer number (155969117374).
Almost surely, 2311938234747 is an apocalyptic number.
311938234747 is a deficient number, since it is larger than the sum of its proper divisors (1).
311938234747 is an equidigital number, since it uses as much as digits as its factorization.
311938234747 is an evil number, because the sum of its binary digits is even.
The product of its digits is 3048192, while the sum is 52.
The spelling of 311938234747 in words is "three hundred eleven billion, nine hundred thirty-eight million, two hundred thirty-four thousand, seven hundred forty-seven".
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