Base | Representation |
---|---|
bin | 1110001100000010100011… |
… | …00101110010110111001111 |
3 | 11002110200200102122222120022 |
4 | 13012001101211302313033 |
5 | 13042140110343102203 |
6 | 150205030510012355 |
7 | 6400061236215566 |
oct | 706012145626717 |
9 | 132420612588508 |
10 | 31200011300303 |
11 | 9a39939aa623a |
12 | 35ba9307a70bb |
13 | 14541c1182611 |
14 | 79c1351b6bdd |
15 | 3918b5997a38 |
hex | 1c6051972dcf |
31200011300303 has 2 divisors, whose sum is σ = 31200011300304. Its totient is φ = 31200011300302.
The previous prime is 31200011300291. The next prime is 31200011300323. The reversal of 31200011300303 is 30300311000213.
It is a weak prime.
It is an emirp because it is prime and its reverse (30300311000213) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 31200011300303 - 240 = 30100499672527 is a prime.
It is a Sophie Germain prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (31200011300323) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15600005650151 + 15600005650152.
It is an arithmetic number, because the mean of its divisors is an integer number (15600005650152).
Almost surely, 231200011300303 is an apocalyptic number.
31200011300303 is a deficient number, since it is larger than the sum of its proper divisors (1).
31200011300303 is an equidigital number, since it uses as much as digits as its factorization.
31200011300303 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 162, while the sum is 17.
Adding to 31200011300303 its reverse (30300311000213), we get a palindrome (61500322300516).
The spelling of 31200011300303 in words is "thirty-one trillion, two hundred billion, eleven million, three hundred thousand, three hundred three".
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