Base | Representation |
---|---|
bin | 101101011001101111000… |
… | …110000010100110111001 |
3 | 102001021021212110121012111 |
4 | 231121233012002212321 |
5 | 402104240042031132 |
6 | 10345151324412321 |
7 | 441261521241613 |
oct | 55315706024671 |
9 | 12037255417174 |
10 | 3120010111417 |
11 | aa3209407741 |
12 | 4248190a70a1 |
13 | 1982a5b47754 |
14 | ab01b711db3 |
15 | 5625a545647 |
hex | 2d66f1829b9 |
3120010111417 has 2 divisors, whose sum is σ = 3120010111418. Its totient is φ = 3120010111416.
The previous prime is 3120010111411. The next prime is 3120010111423. The reversal of 3120010111417 is 7141110100213.
It is a balanced prime because it is at equal distance from previous prime (3120010111411) and next prime (3120010111423).
It can be written as a sum of positive squares in only one way, i.e., 2010097292841 + 1109912818576 = 1417779^2 + 1053524^2 .
It is a cyclic number.
It is not a de Polignac number, because 3120010111417 - 239 = 2570254297529 is a prime.
It is not a weakly prime, because it can be changed into another prime (3120010111411) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1560005055708 + 1560005055709.
It is an arithmetic number, because the mean of its divisors is an integer number (1560005055709).
Almost surely, 23120010111417 is an apocalyptic number.
It is an amenable number.
3120010111417 is a deficient number, since it is larger than the sum of its proper divisors (1).
3120010111417 is an equidigital number, since it uses as much as digits as its factorization.
3120010111417 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 168, while the sum is 22.
The spelling of 3120010111417 in words is "three trillion, one hundred twenty billion, ten million, one hundred eleven thousand, four hundred seventeen".
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