312010113111107 has 2 divisors, whose sum is σ = 312010113111108. Its totient is φ = 312010113111106.

The previous prime is 312010113111071. The next prime is 312010113111121. The reversal of 312010113111107 is 701111311010213.

It is a happy number.

Together with previous prime (312010113111071) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 312010113111107 - 2¹⁴ = 312010113094723 is a prime.

It is not a weakly prime, because it can be changed into another prime (312010113111007) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 156005056555553 + 156005056555554.

It is an arithmetic number, because the mean of its divisors is an integer number (156005056555554).

Almost surely, 2^{312010113111107} is an apocalyptic number.

312010113111107 is a deficient number, since it is larger than the sum of its proper divisors (1).

312010113111107 is an equidigital number, since it uses as much as digits as its factorization.

312010113111107 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 126, while the sum is 23.

The spelling of 312010113111107 in words is "three hundred twelve trillion, ten billion, one hundred thirteen million, one hundred eleven thousand, one hundred seven".