Base | Representation |
---|---|
bin | 1110001100000100011011… |
… | …11100100110110010100011 |
3 | 11002110210022000002001012211 |
4 | 13012002031330212302203 |
5 | 13042144144110204443 |
6 | 150205315201502551 |
7 | 6400125313250551 |
oct | 706021574466243 |
9 | 132423260061184 |
10 | 31201023913123 |
11 | 9a3a309654239 |
12 | 35bab73941a57 |
13 | 1454322bb76bc |
14 | 79c1cd888bd1 |
15 | 39192481b19d |
hex | 1c608df26ca3 |
31201023913123 has 2 divisors, whose sum is σ = 31201023913124. Its totient is φ = 31201023913122.
The previous prime is 31201023913097. The next prime is 31201023913183. The reversal of 31201023913123 is 32131932010213.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 31201023913123 - 213 = 31201023904931 is a prime.
It is a super-2 number, since 2×312010239131232 (a number of 28 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (31201023913183) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15600511956561 + 15600511956562.
It is an arithmetic number, because the mean of its divisors is an integer number (15600511956562).
Almost surely, 231201023913123 is an apocalyptic number.
31201023913123 is a deficient number, since it is larger than the sum of its proper divisors (1).
31201023913123 is an equidigital number, since it uses as much as digits as its factorization.
31201023913123 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5832, while the sum is 31.
Adding to 31201023913123 its reverse (32131932010213), we get a palindrome (63332955923336).
The spelling of 31201023913123 in words is "thirty-one trillion, two hundred one billion, twenty-three million, nine hundred thirteen thousand, one hundred twenty-three".
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