Base | Representation |
---|---|
bin | 100011011110001011100000… |
… | …1011010101000001110110110 |
3 | 1111220201222022002210202200000 |
4 | 1012330113001122220032312 |
5 | 311343442310403414032 |
6 | 3023331535121132130 |
7 | 122502030005603661 |
oct | 10674270132501666 |
9 | 1456658262722600 |
10 | 312011144201142 |
11 | 90464201873611 |
12 | 2abb1a24a8a046 |
13 | 105136a886a659 |
14 | 57095c45006d8 |
15 | 26111d4d04e7c |
hex | 11bc5c16a83b6 |
312011144201142 has 24 divisors (see below), whose sum is σ = 701062077095016. Its totient is φ = 104003714733552.
The previous prime is 312011144201077. The next prime is 312011144201167. The reversal of 312011144201142 is 241102441110213.
312011144201142 is a `hidden beast` number, since 3 + 1 + 201 + 1 + 1 + 442 + 0 + 1 + 14 + 2 = 666.
It is a Harshad number since it is a multiple of its sum of digits (27).
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 320999119063 + ... + 320999120034.
It is an arithmetic number, because the mean of its divisors is an integer number (29210919878959).
Almost surely, 2312011144201142 is an apocalyptic number.
312011144201142 is an abundant number, since it is smaller than the sum of its proper divisors (389050932893874).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
312011144201142 is an equidigital number, since it uses as much as digits as its factorization.
312011144201142 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 641998239114 (or 641998239102 counting only the distinct ones).
The product of its (nonzero) digits is 1536, while the sum is 27.
Adding to 312011144201142 its reverse (241102441110213), we get a palindrome (553113585311355).
The spelling of 312011144201142 in words is "three hundred twelve trillion, eleven billion, one hundred forty-four million, two hundred one thousand, one hundred forty-two".
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