Base | Representation |
---|---|
bin | 100011011110001011100010… |
… | …0111111100000011010111001 |
3 | 1111220201222110021201000210102 |
4 | 1012330113010333200122321 |
5 | 311343442421233400441 |
6 | 3023331545103125145 |
7 | 122502031334565056 |
oct | 10674270477403271 |
9 | 1456658407630712 |
10 | 312011204200121 |
11 | 90464232723748 |
12 | 2abb1a40ba37b5 |
13 | 105136b8116cca |
14 | 57095cc47c02d |
15 | 26111da20769b |
hex | 11bc5c4fe06b9 |
312011204200121 has 2 divisors, whose sum is σ = 312011204200122. Its totient is φ = 312011204200120.
The previous prime is 312011204200081. The next prime is 312011204200141. The reversal of 312011204200121 is 121002402110213.
It is an a-pointer prime, because the next prime (312011204200141) can be obtained adding 312011204200121 to its sum of digits (20).
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 254381318840896 + 57629885359225 = 15949336^2 + 7591435^2 .
It is a cyclic number.
It is not a de Polignac number, because 312011204200121 - 226 = 312011137091257 is a prime.
It is a super-3 number, since 3×3120112042001213 (a number of 44 digits) contains 333 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 312011204200093 and 312011204200102.
It is not a weakly prime, because it can be changed into another prime (312011204200141) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 156005602100060 + 156005602100061.
It is an arithmetic number, because the mean of its divisors is an integer number (156005602100061).
Almost surely, 2312011204200121 is an apocalyptic number.
It is an amenable number.
312011204200121 is a deficient number, since it is larger than the sum of its proper divisors (1).
312011204200121 is an equidigital number, since it uses as much as digits as its factorization.
312011204200121 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 192, while the sum is 20.
Adding to 312011204200121 its reverse (121002402110213), we get a palindrome (433013606310334).
The spelling of 312011204200121 in words is "three hundred twelve trillion, eleven billion, two hundred four million, two hundred thousand, one hundred twenty-one".
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