Base | Representation |
---|---|
bin | 100011011110001011101001… |
… | …0000110000001001100100111 |
3 | 1111220202000000121022120200211 |
4 | 1012330113102012001030213 |
5 | 311343443344021323142 |
6 | 3023332022554320251 |
7 | 122502036644133205 |
oct | 10674272206011447 |
9 | 1456660017276624 |
10 | 312011424011047 |
11 | 90464335807972 |
12 | 2abb1aa2729087 |
13 | 10513721819647 |
14 | 570960d73a075 |
15 | 26111ee676917 |
hex | 11bc5d2181327 |
312011424011047 has 2 divisors, whose sum is σ = 312011424011048. Its totient is φ = 312011424011046.
The previous prime is 312011424011003. The next prime is 312011424011081. The reversal of 312011424011047 is 740110424110213.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-312011424011047 is a prime.
It is a super-2 number, since 2×3120114240110472 (a number of 30 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (312011424021047) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 156005712005523 + 156005712005524.
It is an arithmetic number, because the mean of its divisors is an integer number (156005712005524).
Almost surely, 2312011424011047 is an apocalyptic number.
312011424011047 is a deficient number, since it is larger than the sum of its proper divisors (1).
312011424011047 is an equidigital number, since it uses as much as digits as its factorization.
312011424011047 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5376, while the sum is 31.
The spelling of 312011424011047 in words is "three hundred twelve trillion, eleven billion, four hundred twenty-four million, eleven thousand, forty-seven".
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