Base | Representation |
---|---|
bin | 101101011001110101110… |
… | …001010110111000011011 |
3 | 102001021120200020201201221 |
4 | 231121311301112320123 |
5 | 402110002231124242 |
6 | 10345210405352511 |
7 | 441264351341344 |
oct | 55316561267033 |
9 | 12037520221657 |
10 | 3120122129947 |
11 | aa3266667939 |
12 | 42484a708737 |
13 | 1982c31087c4 |
14 | ab02c5510cb |
15 | 562652c1167 |
hex | 2d675c56e1b |
3120122129947 has 2 divisors, whose sum is σ = 3120122129948. Its totient is φ = 3120122129946.
The previous prime is 3120122129911. The next prime is 3120122130031. The reversal of 3120122129947 is 7499212210213.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 3120122129947 - 227 = 3119987912219 is a prime.
It is not a weakly prime, because it can be changed into another prime (3120122129647) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1560061064973 + 1560061064974.
It is an arithmetic number, because the mean of its divisors is an integer number (1560061064974).
Almost surely, 23120122129947 is an apocalyptic number.
3120122129947 is a deficient number, since it is larger than the sum of its proper divisors (1).
3120122129947 is an equidigital number, since it uses as much as digits as its factorization.
3120122129947 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 108864, while the sum is 43.
The spelling of 3120122129947 in words is "three trillion, one hundred twenty billion, one hundred twenty-two million, one hundred twenty-nine thousand, nine hundred forty-seven".
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