Base | Representation |
---|---|
bin | 101101011001110101110… |
… | …001010110111001101111 |
3 | 102001021120200020201212001 |
4 | 231121311301112321233 |
5 | 402110002231130111 |
6 | 10345210405353131 |
7 | 441264351341524 |
oct | 55316561267157 |
9 | 12037520221761 |
10 | 3120122130031 |
11 | aa3266667a05 |
12 | 42484a7087a7 |
13 | 1982c310885a |
14 | ab02c55114b |
15 | 562652c11c1 |
hex | 2d675c56e6f |
3120122130031 has 2 divisors, whose sum is σ = 3120122130032. Its totient is φ = 3120122130030.
The previous prime is 3120122129947. The next prime is 3120122130053. The reversal of 3120122130031 is 1300312210213.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 3120122130031 - 219 = 3120121605743 is a prime.
It is a super-2 number, since 2×31201221300312 (a number of 26 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 3120122129990 and 3120122130008.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (3120122830031) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1560061065015 + 1560061065016.
It is an arithmetic number, because the mean of its divisors is an integer number (1560061065016).
Almost surely, 23120122130031 is an apocalyptic number.
3120122130031 is a deficient number, since it is larger than the sum of its proper divisors (1).
3120122130031 is an equidigital number, since it uses as much as digits as its factorization.
3120122130031 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 216, while the sum is 19.
Adding to 3120122130031 its reverse (1300312210213), we get a palindrome (4420434340244).
The spelling of 3120122130031 in words is "three trillion, one hundred twenty billion, one hundred twenty-two million, one hundred thirty thousand, thirty-one".
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