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3120122130002 = 21560061065001
BaseRepresentation
bin101101011001110101110…
…001010110111001010010
3102001021120200020201210222
4231121311301112321102
5402110002231130002
610345210405353042
7441264351341453
oct55316561267122
912037520221728
103120122130002
11aa3266667989
1242484a708782
131982c3108837
14ab02c55112a
15562652c11a2
hex2d675c56e52

3120122130002 has 4 divisors (see below), whose sum is σ = 4680183195006. Its totient is φ = 1560061065000.

The previous prime is 3120122129947. The next prime is 3120122130031. The reversal of 3120122130002 is 2000312210213.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 3047674486081 + 72447643921 = 1745759^2 + 269161^2 .

It is a super-2 number, since 2×31201221300022 (a number of 26 digits) contains 22 as substring.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 780030532499 + ... + 780030532502.

Almost surely, 23120122130002 is an apocalyptic number.

3120122130002 is a deficient number, since it is larger than the sum of its proper divisors (1560061065004).

3120122130002 is a wasteful number, since it uses less digits than its factorization.

3120122130002 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1560061065003.

The product of its (nonzero) digits is 144, while the sum is 17.

Adding to 3120122130002 its reverse (2000312210213), we get a palindrome (5120434340215).

The spelling of 3120122130002 in words is "three trillion, one hundred twenty billion, one hundred twenty-two million, one hundred thirty thousand, two".

Divisors: 1 2 1560061065001 3120122130002