Base | Representation |
---|---|
bin | 111011100000… |
… | …1011111011001 |
3 | 2011201012001112 |
4 | 1313001133121 |
5 | 30441414431 |
6 | 3032430105 |
7 | 526130501 |
oct | 167013731 |
9 | 64635045 |
10 | 31201241 |
11 | 16680a55 |
12 | a548335 |
13 | 6605996 |
14 | 4202a01 |
15 | 2b14c2b |
hex | 1dc17d9 |
31201241 has 2 divisors, whose sum is σ = 31201242. Its totient is φ = 31201240.
The previous prime is 31201237. The next prime is 31201243. The reversal of 31201241 is 14210213.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 15960025 + 15241216 = 3995^2 + 3904^2 .
It is an emirp because it is prime and its reverse (14210213) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 31201241 - 22 = 31201237 is a prime.
Together with 31201243, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (31201243) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15600620 + 15600621.
It is an arithmetic number, because the mean of its divisors is an integer number (15600621).
Almost surely, 231201241 is an apocalyptic number.
It is an amenable number.
31201241 is a deficient number, since it is larger than the sum of its proper divisors (1).
31201241 is an equidigital number, since it uses as much as digits as its factorization.
31201241 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 48, while the sum is 14.
The square root of 31201241 is about 5585.8071037228. The cubic root of 31201241 is about 314.8163572231.
Adding to 31201241 its reverse (14210213), we get a palindrome (45411454).
The spelling of 31201241 in words is "thirty-one million, two hundred one thousand, two hundred forty-one".
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