Base | Representation |
---|---|
bin | 101101011001110110011… |
… | …011101011001011000111 |
3 | 102001021121110010022200212 |
4 | 231121312123223023013 |
5 | 402110013101114421 |
6 | 10345211443230035 |
7 | 441264544543052 |
oct | 55316633531307 |
9 | 12037543108625 |
10 | 3120133223111 |
11 | aa3271954343 |
12 | 42485237831b |
13 | 1982c54c0ac8 |
14 | ab02dbdba99 |
15 | 56266262e5b |
hex | 2d6766eb2c7 |
3120133223111 has 2 divisors, whose sum is σ = 3120133223112. Its totient is φ = 3120133223110.
The previous prime is 3120133223059. The next prime is 3120133223183. The reversal of 3120133223111 is 1113223310213.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 3120133223111 - 214 = 3120133206727 is a prime.
It is a super-2 number, since 2×31201332231112 (a number of 26 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (3120133223411) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1560066611555 + 1560066611556.
It is an arithmetic number, because the mean of its divisors is an integer number (1560066611556).
Almost surely, 23120133223111 is an apocalyptic number.
3120133223111 is a deficient number, since it is larger than the sum of its proper divisors (1).
3120133223111 is an equidigital number, since it uses as much as digits as its factorization.
3120133223111 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 648, while the sum is 23.
Adding to 3120133223111 its reverse (1113223310213), we get a palindrome (4233356533324).
The spelling of 3120133223111 in words is "three trillion, one hundred twenty billion, one hundred thirty-three million, two hundred twenty-three thousand, one hundred eleven".
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