Base | Representation |
---|---|
bin | 101101011001110111100… |
… | …011011111101010010001 |
3 | 102001021122202112211202221 |
4 | 231121313203133222101 |
5 | 402110032411102241 |
6 | 10345213354541041 |
7 | 441265163555635 |
oct | 55316743375221 |
9 | 12037582484687 |
10 | 3120152050321 |
11 | aa3281543519 |
12 | 424858737781 |
13 | 1982c9383477 |
14 | ab0324dcdc5 |
15 | 56267c315d1 |
hex | 2d6778dfa91 |
3120152050321 has 2 divisors, whose sum is σ = 3120152050322. Its totient is φ = 3120152050320.
The previous prime is 3120152050277. The next prime is 3120152050349. The reversal of 3120152050321 is 1230502510213.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 3060974190096 + 59177860225 = 1749564^2 + 243265^2 .
It is a cyclic number.
It is not a de Polignac number, because 3120152050321 - 29 = 3120152049809 is a prime.
It is not a weakly prime, because it can be changed into another prime (3120152050391) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1560076025160 + 1560076025161.
It is an arithmetic number, because the mean of its divisors is an integer number (1560076025161).
Almost surely, 23120152050321 is an apocalyptic number.
It is an amenable number.
3120152050321 is a deficient number, since it is larger than the sum of its proper divisors (1).
3120152050321 is an equidigital number, since it uses as much as digits as its factorization.
3120152050321 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1800, while the sum is 25.
Adding to 3120152050321 its reverse (1230502510213), we get a palindrome (4350654560534).
The spelling of 3120152050321 in words is "three trillion, one hundred twenty billion, one hundred fifty-two million, fifty thousand, three hundred twenty-one".
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