Base | Representation |
---|---|
bin | 1110001100000110010011… |
… | …00011101101100011101100 |
3 | 11002110212212200221202012211 |
4 | 13012003021203231203230 |
5 | 13042203221122121304 |
6 | 150210002325340204 |
7 | 6400162146105622 |
oct | 706031143554354 |
9 | 132425780852184 |
10 | 31202024020204 |
11 | 9a3a782140514 |
12 | 35bb1b2867664 |
13 | 145445216153b |
14 | 79c286623512 |
15 | 39198251e204 |
hex | 1c60c98ed8ec |
31202024020204 has 96 divisors (see below), whose sum is σ = 56751522791040. Its totient is φ = 14998666217472.
The previous prime is 31202024020199. The next prime is 31202024020213. The reversal of 31202024020204 is 40202042020213.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 5533252017 + ... + 5533257655.
It is an arithmetic number, because the mean of its divisors is an integer number (591161695740).
Almost surely, 231202024020204 is an apocalyptic number.
It is an amenable number.
31202024020204 is a deficient number, since it is larger than the sum of its proper divisors (25549498770836).
31202024020204 is a wasteful number, since it uses less digits than its factorization.
31202024020204 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 7147 (or 7145 counting only the distinct ones).
The product of its (nonzero) digits is 1536, while the sum is 22.
Adding to 31202024020204 its reverse (40202042020213), we get a palindrome (71404066040417).
Subtracting 31202024020204 from its reverse (40202042020213), we obtain a square (9000018000009 = 30000032).
The spelling of 31202024020204 in words is "thirty-one trillion, two hundred two billion, twenty-four million, twenty thousand, two hundred four".
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