Base | Representation |
---|---|
bin | 100011011110010100110011… |
… | …1000111001110010010110000 |
3 | 1111220210212211010200122222000 |
4 | 1012330221213013032102300 |
5 | 311344304200111014300 |
6 | 3023345035453014000 |
7 | 122503334432240613 |
oct | 10674514707162260 |
9 | 1456725733618860 |
10 | 312031104001200 |
11 | 90471714635841 |
12 | 2abb5875484300 |
13 | 10515539b0b72c |
14 | 570a55932017a |
15 | 26119a227ec00 |
hex | 11bca671ce4b0 |
312031104001200 has 960 divisors, whose sum is σ = 1201615948800000. Its totient is φ = 76604862136320.
The previous prime is 312031104001193. The next prime is 312031104001213. The reversal of 312031104001200 is 2100401130213.
312031104001200 is a `hidden beast` number, since 3 + 1 + 20 + 31 + 10 + 400 + 1 + 200 = 666.
It is a Harshad number since it is a multiple of its sum of digits (18).
It is an unprimeable number.
It is a polite number, since it can be written in 191 ways as a sum of consecutive naturals, for example, 17249761756 + ... + 17249779844.
It is an arithmetic number, because the mean of its divisors is an integer number (1251683280000).
Almost surely, 2312031104001200 is an apocalyptic number.
312031104001200 is a gapful number since it is divisible by the number (30) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 312031104001200, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (600807974400000).
312031104001200 is an abundant number, since it is smaller than the sum of its proper divisors (889584844798800).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
312031104001200 is a wasteful number, since it uses less digits than its factorization.
312031104001200 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 20179 (or 20162 counting only the distinct ones).
The product of its (nonzero) digits is 144, while the sum is 18.
Adding to 312031104001200 its reverse (2100401130213), we get a palindrome (314131505131413).
The spelling of 312031104001200 in words is "three hundred twelve trillion, thirty-one billion, one hundred four million, one thousand, two hundred".
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