Base | Representation |
---|---|
bin | 1110001100001000010100… |
… | …11110110000101100111011 |
3 | 11002110222200121111220210201 |
4 | 13012010022132300230323 |
5 | 13042212433442211103 |
6 | 150210302355223031 |
7 | 6400231143246625 |
oct | 706041236605473 |
9 | 132428617456721 |
10 | 31203113241403 |
11 | 9a40190a63524 |
12 | 35bb4575a7a77 |
13 | 1454596a0a01c |
14 | 79c34b157c15 |
15 | 3919e7e7651d |
hex | 1c610a7b0b3b |
31203113241403 has 2 divisors, whose sum is σ = 31203113241404. Its totient is φ = 31203113241402.
The previous prime is 31203113241397. The next prime is 31203113241409. The reversal of 31203113241403 is 30414231130213.
It is a balanced prime because it is at equal distance from previous prime (31203113241397) and next prime (31203113241409).
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-31203113241403 is a prime.
It is not a weakly prime, because it can be changed into another prime (31203113241409) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15601556620701 + 15601556620702.
It is an arithmetic number, because the mean of its divisors is an integer number (15601556620702).
Almost surely, 231203113241403 is an apocalyptic number.
31203113241403 is a deficient number, since it is larger than the sum of its proper divisors (1).
31203113241403 is an equidigital number, since it uses as much as digits as its factorization.
31203113241403 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5184, while the sum is 28.
Adding to 31203113241403 its reverse (30414231130213), we get a palindrome (61617344371616).
The spelling of 31203113241403 in words is "thirty-one trillion, two hundred three billion, one hundred thirteen million, two hundred forty-one thousand, four hundred three".
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