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312033230009993 is a prime number
BaseRepresentation
bin100011011110010101110010…
…1110101010011011010001001
31111220211002022022011002202102
41012330223211311103122021
5311344323023340304433
63023350030440443145
7122503441216101152
oct10674534565233211
91456732268132672
10312033230009993
11904726057186a8
122abb61694794b5
13105157b84049bb
14570a6bb81a929
152611a78c334e8
hex11bcae5d53689

312033230009993 has 2 divisors, whose sum is σ = 312033230009994. Its totient is φ = 312033230009992.

The previous prime is 312033230009989. The next prime is 312033230010067. The reversal of 312033230009993 is 399900032330213.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 286338752873209 + 25694477136784 = 16921547^2 + 5068972^2 .

It is a cyclic number.

It is not a de Polignac number, because 312033230009993 - 22 = 312033230009989 is a prime.

It is a super-2 number, since 2×3120332300099932 (a number of 30 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (312033230009093) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 156016615004996 + 156016615004997.

It is an arithmetic number, because the mean of its divisors is an integer number (156016615004997).

Almost surely, 2312033230009993 is an apocalyptic number.

It is an amenable number.

312033230009993 is a deficient number, since it is larger than the sum of its proper divisors (1).

312033230009993 is an equidigital number, since it uses as much as digits as its factorization.

312033230009993 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 708588, while the sum is 47.

The spelling of 312033230009993 in words is "three hundred twelve trillion, thirty-three billion, two hundred thirty million, nine thousand, nine hundred ninety-three".