Base | Representation |
---|---|
bin | 1110001100001000111001… |
… | …11110000011000110010111 |
3 | 11002111000111020012021211111 |
4 | 13012010130332003012113 |
5 | 13042214102344324421 |
6 | 150210353235515451 |
7 | 6400241630654626 |
oct | 706043476030627 |
9 | 132430436167744 |
10 | 31203423433111 |
11 | 9a40330069106 |
12 | 35bb523458b87 |
13 | 1454616065a07 |
14 | 79c37a4216bd |
15 | 391a152e9ee1 |
hex | 1c611cf83197 |
31203423433111 has 2 divisors, whose sum is σ = 31203423433112. Its totient is φ = 31203423433110.
The previous prime is 31203423433067. The next prime is 31203423433129. The reversal of 31203423433111 is 11133432430213.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-31203423433111 is a prime.
It is a super-2 number, since 2×312034234331112 (a number of 28 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (31203423430111) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15601711716555 + 15601711716556.
It is an arithmetic number, because the mean of its divisors is an integer number (15601711716556).
Almost surely, 231203423433111 is an apocalyptic number.
31203423433111 is a deficient number, since it is larger than the sum of its proper divisors (1).
31203423433111 is an equidigital number, since it uses as much as digits as its factorization.
31203423433111 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 15552, while the sum is 31.
Adding to 31203423433111 its reverse (11133432430213), we get a palindrome (42336855863324).
The spelling of 31203423433111 in words is "thirty-one trillion, two hundred three billion, four hundred twenty-three million, four hundred thirty-three thousand, one hundred eleven".
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