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31203423433111 is a prime number
BaseRepresentation
bin1110001100001000111001…
…11110000011000110010111
311002111000111020012021211111
413012010130332003012113
513042214102344324421
6150210353235515451
76400241630654626
oct706043476030627
9132430436167744
1031203423433111
119a40330069106
1235bb523458b87
131454616065a07
1479c37a4216bd
15391a152e9ee1
hex1c611cf83197

31203423433111 has 2 divisors, whose sum is σ = 31203423433112. Its totient is φ = 31203423433110.

The previous prime is 31203423433067. The next prime is 31203423433129. The reversal of 31203423433111 is 11133432430213.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-31203423433111 is a prime.

It is a super-2 number, since 2×312034234331112 (a number of 28 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (31203423430111) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15601711716555 + 15601711716556.

It is an arithmetic number, because the mean of its divisors is an integer number (15601711716556).

Almost surely, 231203423433111 is an apocalyptic number.

31203423433111 is a deficient number, since it is larger than the sum of its proper divisors (1).

31203423433111 is an equidigital number, since it uses as much as digits as its factorization.

31203423433111 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 15552, while the sum is 31.

Adding to 31203423433111 its reverse (11133432430213), we get a palindrome (42336855863324).

The spelling of 31203423433111 in words is "thirty-one trillion, two hundred three billion, four hundred twenty-three million, four hundred thirty-three thousand, one hundred eleven".