Base | Representation |
---|---|
bin | 1110001100001010110001… |
… | …00100000011110101111011 |
3 | 11002111010001220112102101111 |
4 | 13012011120210003311323 |
5 | 13042223124323101441 |
6 | 150211040353301151 |
7 | 6400305461206534 |
oct | 706053044036573 |
9 | 132433056472344 |
10 | 31204423253371 |
11 | 9a407a3479945 |
12 | 35bb7622647b7 |
13 | 145474523c134 |
14 | 79c43312368b |
15 | 391a72e93081 |
hex | 1c6158903d7b |
31204423253371 has 2 divisors, whose sum is σ = 31204423253372. Its totient is φ = 31204423253370.
The previous prime is 31204423253369. The next prime is 31204423253387. The reversal of 31204423253371 is 17335232440213.
It is a weak prime.
It is an emirp because it is prime and its reverse (17335232440213) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 31204423253371 - 21 = 31204423253369 is a prime.
Together with 31204423253369, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (31204423253351) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15602211626685 + 15602211626686.
It is an arithmetic number, because the mean of its divisors is an integer number (15602211626686).
Almost surely, 231204423253371 is an apocalyptic number.
31204423253371 is a deficient number, since it is larger than the sum of its proper divisors (1).
31204423253371 is an equidigital number, since it uses as much as digits as its factorization.
31204423253371 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 362880, while the sum is 40.
Adding to 31204423253371 its reverse (17335232440213), we get a palindrome (48539655693584).
The spelling of 31204423253371 in words is "thirty-one trillion, two hundred four billion, four hundred twenty-three million, two hundred fifty-three thousand, three hundred seventy-one".
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