Base | Representation |
---|---|
bin | 101101011010101010000… |
… | …110001010101001100111 |
3 | 102001100211212010011012102 |
4 | 231122222012022221213 |
5 | 402113302000000403 |
6 | 10345433445242315 |
7 | 441325201200506 |
oct | 55325206125147 |
9 | 12040755104172 |
10 | 3121000000103 |
11 | aa3677154767 |
12 | 424a5470339b |
13 | 198402c544bb |
14 | ab0b2d8a83d |
15 | 562b73cab88 |
hex | 2d6aa18aa67 |
3121000000103 has 2 divisors, whose sum is σ = 3121000000104. Its totient is φ = 3121000000102.
The previous prime is 3121000000021. The next prime is 3121000000109. The reversal of 3121000000103 is 3010000001213.
3121000000103 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 3121000000103 - 222 = 3120995805799 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (3121000000109) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1560500000051 + 1560500000052.
It is an arithmetic number, because the mean of its divisors is an integer number (1560500000052).
Almost surely, 23121000000103 is an apocalyptic number.
3121000000103 is a deficient number, since it is larger than the sum of its proper divisors (1).
3121000000103 is an equidigital number, since it uses as much as digits as its factorization.
3121000000103 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 18, while the sum is 11.
Adding to 3121000000103 its reverse (3010000001213), we get a palindrome (6131000001316).
The spelling of 3121000000103 in words is "three trillion, one hundred twenty-one billion, one hundred three", and thus it is an aban number.
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