Base | Representation |
---|---|
bin | 101101011010101010001… |
… | …011001011010000110101 |
3 | 102001100211221120212121120 |
4 | 231122222023023100311 |
5 | 402113302314011313 |
6 | 10345433533334153 |
7 | 441325215310251 |
oct | 55325213132065 |
9 | 12040757525546 |
10 | 3121001313333 |
11 | aa3677971382 |
12 | 424a55037359 |
13 | 1984032c4167 |
14 | ab0b320d261 |
15 | 562b7589d23 |
hex | 2d6aa2cb435 |
3121001313333 has 32 divisors (see below), whose sum is σ = 4431475992960. Its totient is φ = 1947009454080.
The previous prime is 3121001313329. The next prime is 3121001313379. The reversal of 3121001313333 is 3333131001213.
3121001313333 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 3121001313333 - 22 = 3121001313329 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (3121001313383) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 61878541 + ... + 61928957.
It is an arithmetic number, because the mean of its divisors is an integer number (138483624780).
Almost surely, 23121001313333 is an apocalyptic number.
It is an amenable number.
3121001313333 is a deficient number, since it is larger than the sum of its proper divisors (1310474679627).
3121001313333 is a wasteful number, since it uses less digits than its factorization.
3121001313333 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 57397.
The product of its (nonzero) digits is 1458, while the sum is 24.
Adding to 3121001313333 its reverse (3333131001213), we get a palindrome (6454132314546).
The spelling of 3121001313333 in words is "three trillion, one hundred twenty-one billion, one million, three hundred thirteen thousand, three hundred thirty-three".
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