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312102203030213 is a prime number
BaseRepresentation
bin100011011110110101111010…
…0111100011111101011000101
31111221001200100011001120012212
41012331223310330133223011
5311401440302433431323
63023441434523553205
7122511432353100521
oct10675536474375305
91457050304046185
10312102203030213
119049988a139652
122b0075b838b805
131051c15ab56abb
14570db81ca0d81
1526137640d3b78
hex11bdaf4f1fac5

312102203030213 has 2 divisors, whose sum is σ = 312102203030214. Its totient is φ = 312102203030212.

The previous prime is 312102203030207. The next prime is 312102203030251. The reversal of 312102203030213 is 312030302201213.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 266550259418689 + 45551943611524 = 16326367^2 + 6749218^2 .

It is an emirp because it is prime and its reverse (312030302201213) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 312102203030213 - 240 = 311002691402437 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (312102203030713) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 156051101515106 + 156051101515107.

It is an arithmetic number, because the mean of its divisors is an integer number (156051101515107).

Almost surely, 2312102203030213 is an apocalyptic number.

It is an amenable number.

312102203030213 is a deficient number, since it is larger than the sum of its proper divisors (1).

312102203030213 is an equidigital number, since it uses as much as digits as its factorization.

312102203030213 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1296, while the sum is 23.

Adding to 312102203030213 its reverse (312030302201213), we get a palindrome (624132505231426).

The spelling of 312102203030213 in words is "three hundred twelve trillion, one hundred two billion, two hundred three million, thirty thousand, two hundred thirteen".