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3121031214311 is a prime number
BaseRepresentation
bin101101011010101011111…
…101001111010011100111
3102001100221000212000001012
4231122223331033103213
5402113332442324221
610345440522252435
7441326030414153
oct55325375172347
912040830760035
103121031214311
11aa369283442a
12424a6305711b
1319840956304a
14ab0b7194063
15562b9ee465b
hex2d6abf4f4e7

3121031214311 has 2 divisors, whose sum is σ = 3121031214312. Its totient is φ = 3121031214310.

The previous prime is 3121031214299. The next prime is 3121031214341. The reversal of 3121031214311 is 1134121301213.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 3121031214311 - 214 = 3121031197927 is a prime.

It is a super-2 number, since 2×31210312143112 (a number of 26 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (3121031214341) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1560515607155 + 1560515607156.

It is an arithmetic number, because the mean of its divisors is an integer number (1560515607156).

Almost surely, 23121031214311 is an apocalyptic number.

3121031214311 is a deficient number, since it is larger than the sum of its proper divisors (1).

3121031214311 is an equidigital number, since it uses as much as digits as its factorization.

3121031214311 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 432, while the sum is 23.

Adding to 3121031214311 its reverse (1134121301213), we get a palindrome (4255152515524).

The spelling of 3121031214311 in words is "three trillion, one hundred twenty-one billion, thirty-one million, two hundred fourteen thousand, three hundred eleven".