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3121101121223 is a prime number
BaseRepresentation
bin101101011010110000000…
…111111010011011000111
3102001101002220101122022002
4231122300013322123013
5402114003341334343
610345451500455515
7441330536542331
oct55326007723307
912041086348262
103121101121223
11aa3719241538
12424a8254a59b
1319841ab9b397
14ab0c2590451
15562c12028b8
hex2d6b01fa6c7

3121101121223 has 2 divisors, whose sum is σ = 3121101121224. Its totient is φ = 3121101121222.

The previous prime is 3121101121207. The next prime is 3121101121247. The reversal of 3121101121223 is 3221211011213.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 3121101121223 - 24 = 3121101121207 is a prime.

It is a Sophie Germain prime.

It is a junction number, because it is equal to n+sod(n) for n = 3121101121195 and 3121101121204.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (3121101111223) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1560550560611 + 1560550560612.

It is an arithmetic number, because the mean of its divisors is an integer number (1560550560612).

Almost surely, 23121101121223 is an apocalyptic number.

3121101121223 is a deficient number, since it is larger than the sum of its proper divisors (1).

3121101121223 is an equidigital number, since it uses as much as digits as its factorization.

3121101121223 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 144, while the sum is 20.

Adding to 3121101121223 its reverse (3221211011213), we get a palindrome (6342312132436).

The spelling of 3121101121223 in words is "three trillion, one hundred twenty-one billion, one hundred one million, one hundred twenty-one thousand, two hundred twenty-three".