Base | Representation |
---|---|
bin | 100011011110111010000100… |
… | …0100000010001100011001011 |
3 | 1111221002112100200000000112021 |
4 | 1012331310020200101203023 |
5 | 311402112034001024433 |
6 | 3023445511501225311 |
7 | 122512166352403666 |
oct | 10675641040214313 |
9 | 1457075320000467 |
10 | 312111121111243 |
11 | 904a2646168953 |
12 | 2b009286b62237 |
13 | 1051cc4c65441c |
14 | 571038a4706dd |
15 | 2613ad6ecd22d |
hex | 11bdd088118cb |
312111121111243 has 2 divisors, whose sum is σ = 312111121111244. Its totient is φ = 312111121111242.
The previous prime is 312111121111187. The next prime is 312111121111249. The reversal of 312111121111243 is 342111121111213.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 312111121111243 - 29 = 312111121110731 is a prime.
It is not a weakly prime, because it can be changed into another prime (312111121111249) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 156055560555621 + 156055560555622.
It is an arithmetic number, because the mean of its divisors is an integer number (156055560555622).
Almost surely, 2312111121111243 is an apocalyptic number.
312111121111243 is a deficient number, since it is larger than the sum of its proper divisors (1).
312111121111243 is an equidigital number, since it uses as much as digits as its factorization.
312111121111243 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 288, while the sum is 25.
Adding to 312111121111243 its reverse (342111121111213), we get a palindrome (654222242222456).
The spelling of 312111121111243 in words is "three hundred twelve trillion, one hundred eleven billion, one hundred twenty-one million, one hundred eleven thousand, two hundred forty-three".
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