31211130023 has 2 divisors, whose sum is σ = 31211130024. Its totient is φ = 31211130022.

The previous prime is 31211130001. The next prime is 31211130037. The reversal of 31211130023 is 32003111213.

It is a strong prime.

It is an emirp because it is prime and its reverse (32003111213) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 31211130023 - 2⁶ = 31211129959 is a prime.

It is a super-2 number, since 2×31211130023² (a number of 22 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 31211129983 and 31211130010.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (31211130043) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15605565011 + 15605565012.

It is an arithmetic number, because the mean of its divisors is an integer number (15605565012).

Almost surely, 2^31211130023 is an apocalyptic number.

31211130023 is a deficient number, since it is larger than the sum of its proper divisors (1).

31211130023 is an equidigital number, since it uses as much as digits as its factorization.

31211130023 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 108, while the sum is 17.

Adding to 31211130023 its reverse (32003111213), we get a palindrome (63214241236).

The spelling of 31211130023 in words is "thirty-one billion, two hundred eleven million, one hundred thirty thousand, twenty-three".