Base | Representation |
---|---|
bin | 1001000101010110110… |
… | …00101011110001011101 |
3 | 1002211121200201012101101 |
4 | 10202223120223301131 |
5 | 20103201413114442 |
6 | 355214401113101 |
7 | 31356310616422 |
oct | 4425330536135 |
9 | 1084550635341 |
10 | 312113019997 |
11 | 110403732529 |
12 | 505a6028791 |
13 | 2358051526c |
14 | 1116bb7dd49 |
15 | 81bad06cb7 |
hex | 48ab62bc5d |
312113019997 has 2 divisors, whose sum is σ = 312113019998. Its totient is φ = 312113019996.
The previous prime is 312113019979. The next prime is 312113020183. The reversal of 312113019997 is 799910311213.
Together with previous prime (312113019979) it forms an Ormiston pair, because they use the same digits, order apart.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 292788127801 + 19324892196 = 541099^2 + 139014^2 .
It is a cyclic number.
It is not a de Polignac number, because 312113019997 - 211 = 312113017949 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (312113010997) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 156056509998 + 156056509999.
It is an arithmetic number, because the mean of its divisors is an integer number (156056509999).
Almost surely, 2312113019997 is an apocalyptic number.
It is an amenable number.
312113019997 is a deficient number, since it is larger than the sum of its proper divisors (1).
312113019997 is an equidigital number, since it uses as much as digits as its factorization.
312113019997 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 91854, while the sum is 46.
The spelling of 312113019997 in words is "three hundred twelve billion, one hundred thirteen million, nineteen thousand, nine hundred ninety-seven".
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