Base | Representation |
---|---|
bin | 11101000100010101… |
… | …101010110011111101 |
3 | 2222120011120102112101 |
4 | 131010111222303331 |
5 | 1002410043132031 |
6 | 22201022305101 |
7 | 2153305455655 |
oct | 350425526375 |
9 | 88504512471 |
10 | 31211302141 |
11 | 12266a6a288 |
12 | 6070728191 |
13 | 2c35315a26 |
14 | 172127b365 |
15 | c2a148361 |
hex | 74456acfd |
31211302141 has 2 divisors, whose sum is σ = 31211302142. Its totient is φ = 31211302140.
The previous prime is 31211302037. The next prime is 31211302183. The reversal of 31211302141 is 14120311213.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 27034265241 + 4177036900 = 164421^2 + 64630^2 .
It is a cyclic number.
It is not a de Polignac number, because 31211302141 - 231 = 29063818493 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (31211309141) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15605651070 + 15605651071.
It is an arithmetic number, because the mean of its divisors is an integer number (15605651071).
Almost surely, 231211302141 is an apocalyptic number.
It is an amenable number.
31211302141 is a deficient number, since it is larger than the sum of its proper divisors (1).
31211302141 is an equidigital number, since it uses as much as digits as its factorization.
31211302141 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 144, while the sum is 19.
Adding to 31211302141 its reverse (14120311213), we get a palindrome (45331613354).
The spelling of 31211302141 in words is "thirty-one billion, two hundred eleven million, three hundred two thousand, one hundred forty-one".
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