Base | Representation |
---|---|
bin | 1110001100011000111010… |
… | …00000101011000001001110 |
3 | 11002111211122220222010100011 |
4 | 13012030131000223001032 |
5 | 13042334201044234002 |
6 | 150214333514423434 |
7 | 6400664543026150 |
oct | 706143500530116 |
9 | 132454586863304 |
10 | 31212014055502 |
11 | 9a43a39269935 |
12 | 3601120431b7a |
13 | 1455384a70227 |
14 | 79c953310ad0 |
15 | 391d695ae8d7 |
hex | 1c631d02b04e |
31212014055502 has 16 divisors (see below), whose sum is σ = 54952426291680. Its totient is φ = 13015048331808.
The previous prime is 31212014055493. The next prime is 31212014055503. The reversal of 31212014055502 is 20555041021213.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (31212014055503) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 30127426177 + ... + 30127427212.
It is an arithmetic number, because the mean of its divisors is an integer number (3434526643230).
Almost surely, 231212014055502 is an apocalyptic number.
31212014055502 is a deficient number, since it is larger than the sum of its proper divisors (23740412236178).
31212014055502 is a wasteful number, since it uses less digits than its factorization.
31212014055502 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 60254853435.
The product of its (nonzero) digits is 12000, while the sum is 31.
Adding to 31212014055502 its reverse (20555041021213), we get a palindrome (51767055076715).
The spelling of 31212014055502 in words is "thirty-one trillion, two hundred twelve billion, fourteen million, fifty-five thousand, five hundred two".
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