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31212014055493 is a prime number
BaseRepresentation
bin1110001100011000111010…
…00000101011000001000101
311002111211122220222010022211
413012030131000223001011
513042334201044233433
6150214333514423421
76400664543026135
oct706143500530105
9132454586863284
1031212014055493
119a43a39269927
123601120431b71
131455384a7021b
1479c953310ac5
15391d695ae8cd
hex1c631d02b045

31212014055493 has 2 divisors, whose sum is σ = 31212014055494. Its totient is φ = 31212014055492.

The previous prime is 31212014055463. The next prime is 31212014055503. The reversal of 31212014055493 is 39455041021213.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 22106001696804 + 9106012358689 = 4701702^2 + 3017617^2 .

It is a cyclic number.

It is not a de Polignac number, because 31212014055493 - 221 = 31212011958341 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (31212014055463) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15606007027746 + 15606007027747.

It is an arithmetic number, because the mean of its divisors is an integer number (15606007027747).

Almost surely, 231212014055493 is an apocalyptic number.

It is an amenable number.

31212014055493 is a deficient number, since it is larger than the sum of its proper divisors (1).

31212014055493 is an equidigital number, since it uses as much as digits as its factorization.

31212014055493 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 129600, while the sum is 40.

The spelling of 31212014055493 in words is "thirty-one trillion, two hundred twelve billion, fourteen million, fifty-five thousand, four hundred ninety-three".