Base | Representation |
---|---|
bin | 1110001100011001000101… |
… | …10011001111111100110010 |
3 | 11002111211220200202120121101 |
4 | 13012030202303033330302 |
5 | 13042334400431400200 |
6 | 150214351304515014 |
7 | 6401000132526334 |
oct | 706144263177462 |
9 | 132454820676541 |
10 | 31212111200050 |
11 | 9a43a8908aa90 |
12 | 3601148a7ba6a |
13 | 145539bc24101 |
14 | 79c96219b454 |
15 | 391d72d9d26a |
hex | 1c6322ccff32 |
31212111200050 has 48 divisors (see below), whose sum is σ = 63343233720000. Its totient is φ = 11347883236800.
The previous prime is 31212111200047. The next prime is 31212111200051. The reversal of 31212111200050 is 5000211121213.
It is a super-2 number, since 2×312121112000502 (a number of 28 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (31212111200051) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 1773630 + ... + 8097529.
It is an arithmetic number, because the mean of its divisors is an integer number (1319650702500).
Almost surely, 231212111200050 is an apocalyptic number.
31212111200050 is an abundant number, since it is smaller than the sum of its proper divisors (32131122519950).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
31212111200050 is a wasteful number, since it uses less digits than its factorization.
31212111200050 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 9876931 (or 9876926 counting only the distinct ones).
The product of its (nonzero) digits is 120, while the sum is 19.
Adding to 31212111200050 its reverse (5000211121213), we get a palindrome (36212322321263).
The spelling of 31212111200050 in words is "thirty-one trillion, two hundred twelve billion, one hundred eleven million, two hundred thousand, fifty".
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