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312123401322151 is a prime number
BaseRepresentation
bin100011011110111111110010…
…0011101100011111010100111
31111221010201001111101100222111
41012331333210131203322213
5311402312211214302101
63023455302220541451
7122513112565440106
oct10675774435437247
91457121044340874
10312123401322151
11904a7878008091
122b00b7336b1887
1310521158878603
145710bd339003d
1526140a514e251
hex11bdfe4763ea7

312123401322151 has 2 divisors, whose sum is σ = 312123401322152. Its totient is φ = 312123401322150.

The previous prime is 312123401322101. The next prime is 312123401322157. The reversal of 312123401322151 is 151223104321213.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 312123401322151 - 221 = 312123399224999 is a prime.

It is a super-2 number, since 2×3121234013221512 (a number of 30 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (312123401322157) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (31) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 156061700661075 + 156061700661076.

It is an arithmetic number, because the mean of its divisors is an integer number (156061700661076).

Almost surely, 2312123401322151 is an apocalyptic number.

312123401322151 is a deficient number, since it is larger than the sum of its proper divisors (1).

312123401322151 is an equidigital number, since it uses as much as digits as its factorization.

312123401322151 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 8640, while the sum is 31.

Adding to 312123401322151 its reverse (151223104321213), we get a palindrome (463346505643364).

The spelling of 312123401322151 in words is "three hundred twelve trillion, one hundred twenty-three billion, four hundred one million, three hundred twenty-two thousand, one hundred fifty-one".