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312131000141 is a prime number
BaseRepresentation
bin1001000101011000111…
…01010001011101001101
31002211122221112200111122
410202230131101131031
520103221014001031
6355220242330325
731356616503602
oct4425435213515
91084587480448
10312131000141
111104128a3254
12505b00599a5
132358416c1bc
14111703006a9
1581bc6a947b
hex48ac75174d

312131000141 has 2 divisors, whose sum is σ = 312131000142. Its totient is φ = 312131000140.

The previous prime is 312131000131. The next prime is 312131000179. The reversal of 312131000141 is 141000131213.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 291897075625 + 20233924516 = 540275^2 + 142246^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-312131000141 is a prime.

It is a super-2 number, since 2×3121310001412 (a number of 24 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (312131000131) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 156065500070 + 156065500071.

It is an arithmetic number, because the mean of its divisors is an integer number (156065500071).

Almost surely, 2312131000141 is an apocalyptic number.

It is an amenable number.

312131000141 is a deficient number, since it is larger than the sum of its proper divisors (1).

312131000141 is an equidigital number, since it uses as much as digits as its factorization.

312131000141 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 72, while the sum is 17.

Adding to 312131000141 its reverse (141000131213), we get a palindrome (453131131354).

The spelling of 312131000141 in words is "three hundred twelve billion, one hundred thirty-one million, one hundred forty-one", and thus it is an aban number.