Base | Representation |
---|---|
bin | 101101011010111100100… |
… | …101001001110101001100 |
3 | 102001101122110122112020222 |
4 | 231122330211021311030 |
5 | 402114420342104400 |
6 | 10345524324130512 |
7 | 441335655130154 |
oct | 55327445116514 |
9 | 12041573575228 |
10 | 3121310113100 |
11 | aa38162061a3 |
12 | 424b20536a38 |
13 | 19845228340a |
14 | ab102233764 |
15 | 562d4736185 |
hex | 2d6bc949d4c |
3121310113100 has 36 divisors (see below), whose sum is σ = 6774598950000. Its totient is φ = 1248274090560.
The previous prime is 3121310113091. The next prime is 3121310113109. The reversal of 3121310113100 is 13110131213.
It is an interprime number because it is at equal distance from previous prime (3121310113091) and next prime (3121310113109).
It is a super-2 number, since 2×31213101131002 (a number of 26 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (3121310113109) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 2622035 + ... + 3621834.
Almost surely, 23121310113100 is an apocalyptic number.
It is an amenable number.
3121310113100 is an abundant number, since it is smaller than the sum of its proper divisors (3653288836900).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
3121310113100 is a wasteful number, since it uses less digits than its factorization.
3121310113100 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6248882 (or 6248875 counting only the distinct ones).
The product of its (nonzero) digits is 54, while the sum is 17.
Adding to 3121310113100 its reverse (13110131213), we get a palindrome (3134420244313).
The spelling of 3121310113100 in words is "three trillion, one hundred twenty-one billion, three hundred ten million, one hundred thirteen thousand, one hundred".
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