Search a number
-
+
312131134114342 = 2156065567057171
BaseRepresentation
bin100011011111000011011000…
…1010111110100101000100110
31111221011110000101222220200021
41012332012301113310220212
5311402424030313124332
63023503021413305354
7122513505323205544
oct10676066127645046
91457143011886607
10312131134114342
1190500085a69334
122b01113133525a
1310521abb9327aa
14571132837cd94
1526143a8e66c97
hex11be1b15f4a26

312131134114342 has 4 divisors (see below), whose sum is σ = 468196701171516. Its totient is φ = 156065567057170.

The previous prime is 312131134114201. The next prime is 312131134114363. The reversal of 312131134114342 is 243411431131213.

It is a semiprime because it is the product of two primes.

It is a junction number, because it is equal to n+sod(n) for n = 312131134114298 and 312131134114307.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 78032783528584 + ... + 78032783528587.

It is an arithmetic number, because the mean of its divisors is an integer number (117049175292879).

Almost surely, 2312131134114342 is an apocalyptic number.

312131134114342 is a deficient number, since it is larger than the sum of its proper divisors (156065567057174).

312131134114342 is a wasteful number, since it uses less digits than its factorization.

312131134114342 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 156065567057173.

The product of its digits is 20736, while the sum is 34.

Adding to 312131134114342 its reverse (243411431131213), we get a palindrome (555542565245555).

The spelling of 312131134114342 in words is "three hundred twelve trillion, one hundred thirty-one billion, one hundred thirty-four million, one hundred fourteen thousand, three hundred forty-two".

Divisors: 1 2 156065567057171 312131134114342