Base | Representation |
---|---|
bin | 100011011111000011011101… |
… | …1111111001010100110111011 |
3 | 1111221011110110211002121102221 |
4 | 1012332012323333022212323 |
5 | 311402424411410400443 |
6 | 3023503051214304511 |
7 | 122513512615002223 |
oct | 10676067377124673 |
9 | 1457143424077387 |
10 | 312131312200123 |
11 | 90500167543869 |
12 | 2b011180ab8137 |
13 | 10521b197b62b0 |
14 | 5711343c99083 |
15 | 26143b98e2eed |
hex | 11be1bbfca9bb |
312131312200123 has 64 divisors (see below), whose sum is σ = 346433762747520. Its totient is φ = 279489346633728.
The previous prime is 312131312200111. The next prime is 312131312200187. The reversal of 312131312200123 is 321002213131213.
It is a de Polignac number, because none of the positive numbers 2k-312131312200123 is a prime.
It is not an unprimeable number, because it can be changed into a prime (312131312206123) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (31) of ones.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 5134299415 + ... + 5134360207.
It is an arithmetic number, because the mean of its divisors is an integer number (5413027542930).
Almost surely, 2312131312200123 is an apocalyptic number.
312131312200123 is a deficient number, since it is larger than the sum of its proper divisors (34302450547397).
312131312200123 is a wasteful number, since it uses less digits than its factorization.
312131312200123 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 61408.
The product of its (nonzero) digits is 1296, while the sum is 25.
Adding to 312131312200123 its reverse (321002213131213), we get a palindrome (633133525331336).
The spelling of 312131312200123 in words is "three hundred twelve trillion, one hundred thirty-one billion, three hundred twelve million, two hundred thousand, one hundred twenty-three".
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