Base | Representation |
---|---|
bin | 1001000101011000111… |
… | …10100010101111111001 |
3 | 1002211122222011121020221 |
4 | 10202230132202233321 |
5 | 20103221110124423 |
6 | 355220253420041 |
7 | 31356622361425 |
oct | 4425436425771 |
9 | 1084588147227 |
10 | 312131333113 |
11 | 110413000436 |
12 | 505b019a621 |
13 | 23584257922 |
14 | 11170389b85 |
15 | 81bc722e5d |
hex | 48ac7a2bf9 |
312131333113 has 2 divisors, whose sum is σ = 312131333114. Its totient is φ = 312131333112.
The previous prime is 312131333083. The next prime is 312131333123. The reversal of 312131333113 is 311333131213.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 287158800384 + 24972532729 = 535872^2 + 158027^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-312131333113 is a prime.
It is a super-2 number, since 2×3121313331132 (a number of 24 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (312131333123) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 156065666556 + 156065666557.
It is an arithmetic number, because the mean of its divisors is an integer number (156065666557).
Almost surely, 2312131333113 is an apocalyptic number.
It is an amenable number.
312131333113 is a deficient number, since it is larger than the sum of its proper divisors (1).
312131333113 is an equidigital number, since it uses as much as digits as its factorization.
312131333113 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 1458, while the sum is 25.
Adding to 312131333113 its reverse (311333131213), we get a palindrome (623464464326).
The spelling of 312131333113 in words is "three hundred twelve billion, one hundred thirty-one million, three hundred thirty-three thousand, one hundred thirteen".
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