Base | Representation |
---|---|
bin | 100011011111000011110110… |
… | …0001000101101110011110101 |
3 | 1111221011112120010010121020021 |
4 | 1012332013230020231303311 |
5 | 311402433040210304343 |
6 | 3023503303312405141 |
7 | 122513541624164044 |
oct | 10676075410556365 |
9 | 1457145503117207 |
10 | 312132120009973 |
11 | 9050054152930a |
12 | 2b0113675467b1 |
13 | 10521c17c71ba3 |
14 | 57113bd29855b |
15 | 26144157ae0ed |
hex | 11be1ec22dcf5 |
312132120009973 has 2 divisors, whose sum is σ = 312132120009974. Its totient is φ = 312132120009972.
The previous prime is 312132120009967. The next prime is 312132120010031. The reversal of 312132120009973 is 379900021231213.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 179534085335089 + 132598034674884 = 13399033^2 + 11515122^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-312132120009973 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (312132120009953) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 156066060004986 + 156066060004987.
It is an arithmetic number, because the mean of its divisors is an integer number (156066060004987).
Almost surely, 2312132120009973 is an apocalyptic number.
It is an amenable number.
312132120009973 is a deficient number, since it is larger than the sum of its proper divisors (1).
312132120009973 is an equidigital number, since it uses as much as digits as its factorization.
312132120009973 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 122472, while the sum is 43.
The spelling of 312132120009973 in words is "three hundred twelve trillion, one hundred thirty-two billion, one hundred twenty million, nine thousand, nine hundred seventy-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.074 sec. • engine limits •