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31213423131001 is a prime number
BaseRepresentation
bin1110001100011011100001…
…11111110111100101111001
311002111222022010101120112121
413012031300333313211321
513042400042310143001
6150215125412041241
76401044503001036
oct706156077674571
9132458263346477
1031213423131001
119a445a1697141
123601454303221
13145554a978807
1479ca4850638d
15391ded1486a1
hex1c6370ff7979

31213423131001 has 2 divisors, whose sum is σ = 31213423131002. Its totient is φ = 31213423131000.

The previous prime is 31213423130963. The next prime is 31213423131017. The reversal of 31213423131001 is 10013132431213.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 31162921805376 + 50501325625 = 5582376^2 + 224725^2 .

It is an emirp because it is prime and its reverse (10013132431213) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 31213423131001 - 237 = 31075984177529 is a prime.

It is not a weakly prime, because it can be changed into another prime (31213423131101) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15606711565500 + 15606711565501.

It is an arithmetic number, because the mean of its divisors is an integer number (15606711565501).

Almost surely, 231213423131001 is an apocalyptic number.

It is an amenable number.

31213423131001 is a deficient number, since it is larger than the sum of its proper divisors (1).

31213423131001 is an equidigital number, since it uses as much as digits as its factorization.

31213423131001 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1296, while the sum is 25.

Adding to 31213423131001 its reverse (10013132431213), we get a palindrome (41226555562214).

The spelling of 31213423131001 in words is "thirty-one trillion, two hundred thirteen billion, four hundred twenty-three million, one hundred thirty-one thousand, one".