Search a number
-
+
31214113000453 is a prime number
BaseRepresentation
bin1110001100011100110100…
…00111100000110000000101
311002112001002012111120112001
413012032122013200300011
513042403000412003303
6150215322054225301
76401100550540165
oct706163207406005
9132461065446461
1031214113000453
119a44916047289
123601607355231
13145562a87baa6
1479cab1da45a5
15391e3d9b931d
hex1c639a1e0c05

31214113000453 has 2 divisors, whose sum is σ = 31214113000454. Its totient is φ = 31214113000452.

The previous prime is 31214113000403. The next prime is 31214113000501. The reversal of 31214113000453 is 35400031141213.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 30970927913409 + 243185087044 = 5565153^2 + 493138^2 .

It is a cyclic number.

It is not a de Polignac number, because 31214113000453 - 29 = 31214112999941 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (31214113000403) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15607056500226 + 15607056500227.

It is an arithmetic number, because the mean of its divisors is an integer number (15607056500227).

Almost surely, 231214113000453 is an apocalyptic number.

It is an amenable number.

31214113000453 is a deficient number, since it is larger than the sum of its proper divisors (1).

31214113000453 is an equidigital number, since it uses as much as digits as its factorization.

31214113000453 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 4320, while the sum is 28.

Adding to 31214113000453 its reverse (35400031141213), we get a palindrome (66614144141666).

The spelling of 31214113000453 in words is "thirty-one trillion, two hundred fourteen billion, one hundred thirteen million, four hundred fifty-three", and thus it is an aban number.