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312141404342302 = 2156070702171151
BaseRepresentation
bin100011011111001000001010…
…1100001101000100000011110
31111221012102112011020112212121
41012332100111201220200132
5311403111044002423202
63023511440452053154
7122514320661541243
oct10676202541504036
91457172464215777
10312141404342302
1190504476272637
122b0131189041ba
1310522a675c5762
145711a203655ca
1526147aa902537
hex11be41586881e

312141404342302 has 4 divisors (see below), whose sum is σ = 468212106513456. Its totient is φ = 156070702171150.

The previous prime is 312141404342279. The next prime is 312141404342321. The reversal of 312141404342302 is 203243404141213.

It is a semiprime because it is the product of two primes.

It is a super-2 number, since 2×3121414043423022 (a number of 30 digits) contains 22 as substring.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 78035351085574 + ... + 78035351085577.

It is an arithmetic number, because the mean of its divisors is an integer number (117053026628364).

Almost surely, 2312141404342302 is an apocalyptic number.

312141404342302 is a deficient number, since it is larger than the sum of its proper divisors (156070702171154).

312141404342302 is a wasteful number, since it uses less digits than its factorization.

312141404342302 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 156070702171153.

The product of its (nonzero) digits is 55296, while the sum is 34.

Adding to 312141404342302 its reverse (203243404141213), we get a palindrome (515384808483515).

The spelling of 312141404342302 in words is "three hundred twelve trillion, one hundred forty-one billion, four hundred four million, three hundred forty-two thousand, three hundred two".

Divisors: 1 2 156070702171151 312141404342302